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Moles of an ideal gas

A-Level (AQA) · C3L6 · UKChO Round 1 · IChO · unreviewed

n = pV/RT in SI units: Pa × m³ (or kPa × dm³, which also gives J) and T in kelvin.

Worked example

How many moles of an ideal gas occupy 18900 cm³ at 3.56 atm and 64 °C?

  1. 1. Ideal gas equation: solve for n

    n=pVRTn = \dfrac{pV}{RT}

    = 2.432 mol

Answer: n = 2.43 mol

Method

n = pV/RT in SI units: Pa × m³ (or kPa × dm³, which also gives J) and T in kelvin.

Formulas used

  • Ideal gas equation

    pV=nRTpV = nRT

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