UnoffIChO
All question types · Kinetics

Radioactive decay: elapsed time

C3L6 · UKChO Round 1 · IChO · unreviewed

t = t½ · ln(N₀/N) / ln 2.

Worked example

A radioisotope (half-life 576 yr) decays from 74.4 mg to 27.6 mg. How much time has passed?

  1. 1. Radioactive decay: solve for t

    t=t1/2 ln⁡(N0/N)ln⁡2t = t_{1/2}\,\dfrac{\ln(N_0/N)}{\ln 2}

    = 824.0 yr

Answer: t = 824 yr

Method

t = t½ · ln(N₀/N) / ln 2.

Formulas used

  • Radioactive decay

    N=N0(12)t/t1/2N = N_0\left(\tfrac{1}{2}\right)^{t/t_{1/2}}

More kinetics questions

Unofficial and independent. Not affiliated with the International Chemistry Olympiad, the Royal Society of Chemistry, the University of Cambridge or any exam board.