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Second-order half-life

UKChO Round 1 · UKChO Round 2 · IChO · unreviewed

t½ = 1/(k[A]₀).

Worked example

A second-order reaction (rate = k[A]²) has k = 0.58 dm³ mol⁻¹ s⁻¹. What is the first half-life when [A]₀ = 0.74 mol dm⁻³?

  1. 1. Half-life (second order): solve for t½

    t1/2=1k[A]0t_{1/2} = \dfrac{1}{k[\mathrm{A}]_0}

    = 2.330 s

Answer: t½ = 2.33 s

Method

t½ = 1/(k[A]₀). Unlike first order, it depends on the starting concentration.

Common mistakes

  • ln 2 belongs to the first-order half-life. For second order, t½ = 1/(k[A]₀).

Formulas used

  • Half-life (second order)

    t1/2=1k[A]0t_{1/2} = \dfrac{1}{k[\mathrm{A}]_0}

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